5x^2-45x-450=0

Solution for 5x^2-45x-450=0 equation:

5x^2-45x-450=0

a = 5; b = -45; c = -450;
Δ = b2-4ac
Δ = -452-4·5·(-450)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-105}{2*5}=\frac{-60}{10}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+105}{2*5}=\frac{150}{10}
=15
$